Pool Table Location
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Last two physic problems, please help?
A pool ball leaves a 0.60-meter high table with an initial horizontal velocity of 3.0 m/s. Predict
(a) the time required for the pool ball to fall to the ground
___0.35 s____
(b) the horizontal distance between the table’s edge and the ball’s landing location
A football is kicked with an initial velocity of 22 m/s at an angle of 40-degrees with the horizontal. Determine
(a) the total time of flight
(b) the horizontal distance
(c) the peak height of the football
(1) a) Time taken to fall to the ground is found from
s = 1/2 gt² where s is vertical height fallen. The
horizontal speed has no influence on this time
t² = 2s / g
= 2(0.6) / 9.8
t² = 0.1225
t = √0.1225
t = 0.35 s.
(b) Horizontal distance = horizontal speed times time of flight.
= 3 X 0.35
Horizontal distance = 1.05 m.
(2)(a) Assuming no air resistance, the time of flight is twice the time
ball takes to reach maximum height.
At max ht vertical velocity = 0
22sin40° – gt = 0
t = 22sin40° / g
t = 1.44 s
Total time of flight = 2 X 1.44 = 2.88 s.
(b) Horizontal distance x given by
x = 22cos40° X 2.88
x = 48.54 m.
(c) Peak height y found from
y = 22*t*sin40° – 1/2 gt²
Where t = 1.44 s
y = 22(1.44)(sin40°) – 1/2(9.8)(1.44²)
y = 10.2 m
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